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Tricks in Java

P K Subudhi
14/05/2017 0 0
  1. Find out the compatible and incompatible assignments

class Qs1

{

     public static void main(String arg[])

     {

           /* PART 1

           int a=2.7f;     // not ok

           int b=2.7;      // not ok

           float c=5;      // ok

           float d=2.6;    // not ok

           byte e=5;       // ok

           int f=5;        // ok

           byte g=f;       // not ok

           */

           /* PART 2

           char a='a';     // ok

           char b=65535;   // ok

           byte c=65;      // ok

           char d=c;       // not ok

           boolean e=0;    // not ok

           double f=50L;   // ok

           **/

     }

}

  1. Can we define the class like this and what would be its output?

class Qs2

{

     public static void main(String arg[])

     {

           main();

           System.out.println("I am in main");

     }

     static void main()

     {

           System.out.println("I am in mini main");

     }

}

Ans: Yes. There would be no error. Output is

I am in mini main

I am in main

 

  1. Is it correct to execute this program like this? What would be its output?

class Qs3

{

     public static void main(String arg[])

     {

           String str[]={"Hay","Hello", "hi"};

           System.out.println("I am in main");

           main(str);

     }

}

Ans: Yes. It displays all correct way like a recursive function but after certain time it stops function when stack overflows

 

  1. Let the following classes are defined in a single program Qs4.java. What would the o/p if executed?

class Abc

{

     public static void main(String arg[])

     {

           System.out.println("I am in Abc main");

     }

}

class Xyz

{

     public static void main(String arg[])

     {

           System.out.println("I am in Xyz main");

     }

}

class Qs4

{

     public static void main(String arg[])

     {

           System.out.println("I am in main");

     }

}

Ans: The above code is absolutely valid. When we compile the program, system creates 3 .class files based on 3 classes (as defined in the program given above). While executing we have to use only one class as the start-up. So, system displays the code defined within its own main() method.

 

That is: if the code is executed as

                java Qs4

Output would be

                I am in main

But if it is executed as

                java Abc

Then the output would be

                I am in Abc main

 

  1. What would be the output to the following code?

class Abc

{

     public static void main(String arg[])

     {

           System.out.println(arg[0]);

     }

}

class Xyz

{

     public static void main(String arg[])

     {

           System.out.println(arg[1]);

     }

}

class Qs5

{

     public static void main(String arg[])

     {

           String str[]={"Ni","Tini"};

           System.out.println("I am in main");

           Abc.main(str);

           Xyz.main(str);

     }

}

 

Ans:

I am in main

Ni

Tini

 

 

 

 

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