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Find the distance between the following pairs of points:

(i) (2, 3), (4, 1) (ii) (– 5, 7), (– 1, 3) (iii) (a, b), (– a, – b)

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(i) Distance between two points (x1, y1) and (x2, y2) is given as: √{(x2 – x1)2 + (y2 – y1)2} Therefore, the distance between two points (2, 3) and (4, 1) is D = √{(4 – 2)2 + (1 - 3)2} => D = √{22 + (-2)2} => D = √{4 + 4} => D = √8 =>...
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(i) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(4 – 2)2 + (1 - 3)2}

=> D = √{22 + (-2)2}

=> D = √{4 + 4}

=> D = √8

=> D = 2√2

(ii) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(-1 + 5)2 + (3 - 7)2}

=> D = √{42 + (-4)2}

=> D = √{16 + 16}

=> D = √32

=> D = 4√2

(iii) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(-a - a)2 + (-b - b)2}

=> D = √{(-2a)2 + (-2b)2}

=> D = √{4a2 + 4b2}

=> D = 2√(a2 + b2)

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Physicist

The general formula is
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The general formula is  

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Tutor

1. 2√2 2. 4√2 3. 2√(a²+b²)
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Related Questions

Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer:

(i) (– 1, – 2), (1, 0), (– 1, 2), (– 3, 0)

(ii) (–3, 5), (3, 1), (0, 3), (–1, – 4)

(iii) (4, 5), (7, 6), (4, 3), (1, 2)

(i) Let the points (−1, −2), (1, 0), (−1, 2), and (−3, 0) be representing the vertices A, B, C, and D of the given quadrilateral respectively. Diagonal AC Diagonal BD It can...
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