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A wire stretched between two rigid supports vibrates in its fundamental mode with a frequency of 45 Hz. The mass of the wire is 3.5 x 10-2 kg and its linear mass density is 4.0 x 10-2 kg m-3. What is (a) the speed of a transverse wave on the string, and (b) the tension in the string?

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Sure! Let's tackle this problem step by step. (a) To find the speed of a transverse wave on the string, we can use the formula: v=Tμv=μT Where: vv is the speed of the wave TT is the tension in the string μμ is the linear mass density of the wire Given that the frequency of the fundamental...
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Sure! Let's tackle this problem step by step.

(a) To find the speed of a transverse wave on the string, we can use the formula:

v=Tμv=μT

Where:

  • vv is the speed of the wave
  • TT is the tension in the string
  • μμ is the linear mass density of the wire

Given that the frequency of the fundamental mode is f=45f=45 Hz, we know that f=1Tf=T1, where TT is the period of the wave. Since the wire is vibrating in its fundamental mode, the frequency is the same as the frequency of the wave. So, T=1fT=f1.

Let's first find the period of the wave: T=145T=451 seconds.

Now, let's use the formula for wave speed:

v=Tμv=μT

v=1454.0×10−2v=4.0×10−2451

v=145×4.0×10−2v=45×4.0×10−21

v=11.8v=1.81

v=0.55556v=0.55556

v≈0.745 m/sv≈0.745m/s

So, the speed of the transverse wave on the string is approximately 0.745 m/s0.745m/s.

(b) Now, let's find the tension in the string. We'll use the formula:

T=μv2Tv2

T=(4.0×10−2)×(0.745)2T=(4.0×10−2)×(0.745)2

T=4.0×10−2×0.55556T=4.0×10−2×0.55556

T≈0.0222 NT≈0.0222N

So, the tension in the string is approximately 0.0222 N0.0222N.

If you have any further questions or need clarification, feel free to ask! And remember, UrbanPro is here to support your learning journey.

 
 
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