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The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [B(OH)4]- and the geometry of the complex are respectively
(a) sp3, tetrahedral
(b) sp3, square planar                          
(c) sp3d2, octahedral                              
(d) dsp2, square planar

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Answer : Option (a). Boron has +3 oxidation state. Hence the valence orbitals 2s, 2p will be empty. The electrons donated by hydroxide ions go into empty orbitals of 2s and 2p. Becausse we have 4 OH- groups four orbitals (s+p+p+p) will be involved in hybridisation.. Hence sp3 hybridisation or tetrahedral...
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Answer : Option (a).

Boron has +3 oxidation state. Hence the valence orbitals 2s, 2p will be empty.

The electrons donated by hydroxide ions go into empty orbitals of 2s and 2p. Becausse we have 4 OH- groups four orbitals (s+p+p+p) will be involved in hybridisation.. Hence sp3 hybridisation or tetrahedral shape.

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