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Asked by Anand Last Modified
Answer 
In question, it is given that numbers are in the ratio 5:3. So that we can assume the numbers as 5k and 3k.
where k is a numerical constant.
Now the ratio becomes 5k:3k=5:3
They are differed by 18, that means
5k=3k+18
5k-3k=18
2k=18
k=18/2
k=9
first number=5k=5*9=45
second number=3k=3*9=27
Hence the numbers are 45 and 27
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Let the common ratio between these numbers be x. Therefore, the numbers will be 5x and 3x respectively.
Difference between these numbers = 18
5x − 3x = 18
2x = 18
Dividing both sides by 2,
x = 9
First number = 5x = 5 × 9 = 45
Second number = 3x = 3 × 9 = 27
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