UrbanPro

Take Class 9 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m.
Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.

Asked by Last Modified  

4 Answers

Learn Exercise 13.7

Follow 4
Answer

Please enter your answer

Maths Teacher for classes 6th to 10th with 6 years experience and having my own YouTube Channel for clearing doubts

Diameter of the cone = 10.5m (Radius of the cone = 5.25m) Height of the cone = 3m Volume of the cone = (πr²h)/3 ∴ Volume of the cone = (π x 5.25² x 3)/3 = 86.625m³ The heap is to be covered by canvas to protect it from rain and we have to find the area of the canvas required....
read more

Diameter of the cone = 10.5m (Radius of the cone = 5.25m)

Height of the cone = 3m

Volume of the cone = (πr²h)/3

∴ Volume of the cone = (π x 5.25² x 3)/3 = 86.625m³

The heap is to be covered by canvas to protect it from rain and we have to find the area of the canvas required. So, that means, we have to find the lateral surface area.

Lateral surface area of the cone = πr√r² + h²

∴ Lateral surface area of the cone = π x 5.25√5.25² + 3² = 99.77m²

∴ The area of the canvas required = 99.77m²

read less
Comments

Professional in Adaptive Learning for 8-12th with 11 Yrs of Experience in Quality Teaching

Volume - 86.59 m3 Area of canvas required - 99.73 m2
Comments

Comments

Experienced Maths Teacher

V = (1/3)*π*r*r*h r =10.5/2= 5.25 V= (1/3)*(22/7)*5.25*5.25*3 = 86.625 m^3 Area of the canvas = curved surface of heap = π*r*l l = √(r*r+h*h) = √(36.5625) =6.046 m (approx) πrl = 3.14*5.25*6.046 = 99.668 m^2
read more

V = (1/3)*π*r*r*h

r =10.5/2= 5.25

V= (1/3)*(22/7)*5.25*5.25*3

= 86.625 m^3

Area of the canvas = curved surface of heap = π*r*l

l = √(r*r+h*h) = √(36.5625)

=6.046 m (approx)

πrl = 3.14*5.25*6.046

= 99.668 m^2

 

read less
Comments

View 2 more Answers

Related Questions

The volume of a right circular cone is 9856 cm3 . If the diameter of the base is 28 cm,
find
(i) height of the cone
(ii) slant height of the cone
(iii) curved surface area of the cone
(i) Radius of cone = Let the height of the cone be h. Volume of cone = 9856 cm3 h = 48 cm Therefore, the height of the cone is 48 cm. (ii) Slant height (l) of cone Therefore, the slant height of the...
User
0 0
5
The height of a cone is 15 cm. If its volume is 1570 cm 3 , find the radius of the base.
(Use π = 3.14)
given h = 15 cm volume of cone = 1570 to find- radius (r) formula- volume of cone = 1570 = 3.14 * * 15 /3 1570 *3 = 3.14 * 15 * = 1570 * 3 / 3.14 *...
Vikas
0 0
5

Find the volume of the right circular cone with
(i) radius 6 cm, height 7 cm
(ii) radius 3.5 cm, height 12 cm

(i) Radius (r) of cone = 6 cm Height (h) of cone = 7 cm Volume of cone Therefore, the volume of the cone is 264 cm3. (ii) Radius (r) of cone = 3.5 cm Height (h) of cone = 12 cm Volume of cone Therefore, the volume of the cone is 154 cm3.
D Goutham
0 0
6

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Recommended Articles

Once over with the tenth board exams, a heavy percentage of students remain confused between the three academic streams they have to choose from - science, arts or commerce. Some are confident enough to take a call on this much in advance. But there is no worry if as a student you take time to make choice between - science,...

Read full article >

With the mushrooming of international and private schools, it may seem that the education system of India is healthy. In reality, only 29% of children are sent to the private schools, while the remaining head for government or state funded education. So, to check the reality of Indian education system it is better to look...

Read full article >

Appearing for exams could be stressful for students. Even though they might have prepared well, they could suffer from anxiety, tension etc. These are not good for their health and mind. However, following a few exam preparation tips can save them from all these and help them to score good marks. Let’s find out all...

Read full article >

While schools provide formal education to the children, the home is where they start learning about things informally. Parents think that schools will take the initiative to educate their children. Well, this is partially true, as parents also play an essential role in bringing up their child. For the development of particular...

Read full article >

Looking for Class 9 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 9 Tuition Classes?

The best tutors for Class 9 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 9 Tuition with the Best Tutors

The best Tutors for Class 9 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more