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Class 10 > Learn Mathematics > How many triangles can be drawn having its angles as...
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How many triangles can be drawn having its angles as 45°, 64° and 72°? Give reason for your answer.

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Tutor

Zero triangles.. we cant draw triangle with these angles. but the given angles are 45,64.72. if we add those we get 45+64+72=181. so we cannot draw triangle.
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Dedicated and responsible teacher from NIT Warangal

The sum of all three angles in any triangle anouamo to 180°. If we add the given angles, i.e., 45°+64°+72°,gives us 181°. So, no triangle exists with the given angles.
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Physics Teacher

sum of all angles should be zero
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Trainer

Zero triangles. because we cant draw triangle with these angles. As the given angles are 45,64,72. if we add then we get, 45+64+72=181.so we can't draw triangle.
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Tutor

Zero triangle.For a triangle the sum of its three angle=180 degrees..But if we add 45+64+72 we get 181...so we can't construct a triangle
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Tutor

Zero triangles.. we cant draw triangle with these angles. but the given angles are 45,64.72. if we add those we get 45+64+72=181. so we cannot draw triangle.
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Tutor

not a single triangle becaues the sum of all anglesof triangle should be 180 degre
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Computer Wizard

no traingle can be drawn with this measurements because the total sum of traingle =180 so its exceeds the angle
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Tutor

Only one distinct triangle can be formed.We can make infinite numbers of triangle by scaling up or down its length.
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Teacher

No triangles can be drawn with the three angles mentioned because the sum of all angles in a triangle must be 180, which in this case is not.
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Related Questions

is zero a rational number, can you write it in the form of p/q , where p and q are integeres and q !=0
Yes, of course 0 is a rational number. All natural numbers whole numbers and integers are also rational numbers. 0 can be written as 0/1 , 0/2 etc Hence it is natural number
Murali

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Solve : x + y = 18; y + z = 12; z + x = 16
Let x+y=18---(1), y+z=12---(2),z+x=16---(3) Solving (2)-(3) we get y+z-z-x=12-16 y-x=-4--(4) Solving (4)+(5) we get x+y+y-x=18-4 2y=14 y=14/2=7 Substitute y value in (1) x+7=18 x=18-7=11 Substitute x value in (3) z+11=16 z=16-11=5 x=11, y=7, z=5
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In a GK test a student was given 50 questions one by one. He gave the correct answer for 30 questions. Find the probability of giving correct answers.
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Given that HCF (161,345) = 23, find their LCM.
N¹ *N² = LCM * HCF 161 *345 =23 * N² N² =2415
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