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The moment of inertia of a body about a given axis is 1.2kgm^2 . Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angular acceleration of 25rad/second ^2 must be applied about that axis for a duration of
Asked by Abu Ashraf Last Modified
Answer 
The correct option is B 2 s
I=1.2 kgm2;t=?
Krot=1500 J
α=25rad/s2
ω=ω0+αt
Initially the body was at rest, ωo=0
Rotational kinetic energy, K=12Iω2⇒1500=12×1.2×w2
w=√30001.2=50 rad/s
ω=ω0+αt
ωo=0
t=wα=5025=2s
Rotation kinetic energy= ½Iω²
Where I = moment of Inertia
ω = angular velocity
And, kinematic relation for constant angular acceleration is
ω(final) = ω(initial) + αt
Where, α = angular acceleration
t = time
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