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Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

Let Baichung's, his father's, his grandfather's ages are x,y, and z respectively. z=y+26............(1) y=x+29..................(2) substitute (2) in (1) z=y+26=x+29+26=x+55.............(3) x+y+z=135............(4) replace the values of y and z with (1) and (3) in (4) x+y+z=135 x+x+29+x+55=135 3x+84=135 3x=51 x=51/3=17 y=x+29=17+29=46 z=x+55=72 so...
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Let Baichung's, his father's, his grandfather's ages are x,y, and z respectively.

z=y+26............(1)

y=x+29..................(2)

substitute (2) in (1)

z=y+26=x+29+26=x+55.............(3)

x+y+z=135............(4)

replace the values of y and z with (1) and (3) in (4)

x+y+z=135

x+x+29+x+55=135

3x+84=135

3x=51

x=51/3=17

y=x+29=17+29=46

z=x+55=72

so the ages are 17,46 and 72 respectively

 

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Let Baichung’s father’s age be x years. Therefore, Baichung’s age and Baichung’s grandfather’s age will be (x − 29) years and (x + 26) years respectively. According to the given question, the sum of the ages of these 3 people is 135 years. ∴ x + x − 29...
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Let Baichung’s father’s age be x years. Therefore, Baichung’s age and Baichung’s grandfather’s age will be (x − 29) years and (x + 26) years respectively.

According to the given question, the sum of the ages of these 3 people is 135 years.

x + x − 29 + x + 26 = 135

3x − 3 = 135

On transposing 3 to R.H.S, we obtain

3x = 135 + 3

3x = 138

On dividing both sides by 3, we obtain

x = 46

Baichung’s father’s age = x years = 46 years

Baichung’s age = (x − 29) years = (46 − 29) years = 17 years

Baichung’s grandfather’s age = (x + 26) years = (46 + 26) years = 72 years

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Comments

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