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Answered on 24 Feb Learn Practical Geometry
Sadika
To draw a parallelogram given the lengths of its adjacent sides, you can follow these steps:
By following these steps, you'll have drawn a parallelogram with adjacent sides of lengths 2.8 cm and 3.8 cm.
Answered on 24 Feb Learn Practical Geometry
Sadika
To draw a rectangle given the lengths of its adjacent sides, you can follow these steps:
By following these steps, you'll have drawn a rectangle with adjacent sides of lengths 4.5 cm and 2.3 cm.
Answered on 24 Feb Learn Visualizing Solid Shapes
Sadika
A polyhedron is a three-dimensional geometric figure with flat faces, straight edges, and vertices.
Out of the options provided, a cone is not a polyhedron.
However, a cone does not have flat faces; it has a curved surface. Therefore, a cone is not considered a polyhedron.
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Answered on 24 Feb Learn Playing with Numbers
Sadika
If 3x123x12 is a multiple of 3, it means the sum of its digits is also a multiple of 3.
Let's sum the digits:
3+x+1+2=6+x3+x+1+2=6+x
For 3x123x12 to be a multiple of 3, 6+x6+x must be divisible by 3.
We know that if a number is divisible by 3, then the sum of its digits is also divisible by 3.
Let's try different values of xx from 0 to 9 and see if 6+x6+x is divisible by 3:
Therefore, the value of xx that makes 3x123x12 a multiple of 3 is x=0x=0, x=3x=3, or x=6x=6.
Answered on 24 Feb Learn Playing with Numbers
Sadika
To determine the value of xx such that 35x35x is a multiple of 9, we can sum the digits of the number and see if the result is a multiple of 9.
The number 35x35x can be written as 350+10x350+10x.
Now, let's consider the sum of the digits:
3+5+x=8+x3+5+x=8+x
For the entire number to be divisible by 9, the sum 8+x8+x must be a multiple of 9.
To find the value of xx, we need to find a digit such that 8+x8+x is divisible by 9.
Let's try different values of xx from 0 to 9:
So, x=1x=1 is the value that makes 35x35x a multiple of 9.
Answered on 26 Feb Learn Playing with Numbers
Nazia Khanum
Are you seeking the best online coaching for Class 7 Tuition? As a registered tutor on UrbanPro.com specializing in Class 7 Tuition, I am here to provide guidance on solving mathematical problems. Let's delve into the question of divisibility.
Problem Analysis: The problem at hand is to determine which number among the given options (15, 12, 3, 9) divides 345111 without leaving a remainder. Let's analyze each option systematically.
Options Analysis:
Option 15:
Option 12:
Option 3:
Option 9:
Conclusion: After carefully applying the divisibility rules to each option, the correct answer can be determined. Share the result with the student, emphasizing the importance of understanding and applying these rules to solve similar problems in the future.
By choosing the best online coaching for Class 7 Tuition on UrbanPro.com, students can receive personalized guidance and support to excel in their studies.
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Answered on 26 Feb Learn Playing with Numbers
Nazia Khanum
To find a 5-digit number divisible by 11 with the given digits (2, 3, 4, 5, 6), we can use the following approach:
Alternate Sum Method:
Example: 6−5+4−3+2=46−5+4−3+2=4.
Check Divisibility:
Let's apply the method:
Since 4 is not divisible by 11, let's try another arrangement until we find a suitable number.
After a few iterations, we find the arrangement 5, 6, 4, 3, 2, which yields 2−3+4−6+5=22−3+4−6+5=2. This number, 56432, is divisible by 11.
As your dedicated Class 7 Tuition online coach, I am not only committed to teaching the curriculum but also to engaging students with interesting problem-solving methods. If you have more questions or need further clarification, feel free to reach out!
read lessAnswered on 26 Feb Learn Factorization
Nazia Khanum
As a registered tutor on UrbanPro.com specializing in Class 7 Tuition, I understand the importance of providing clear and structured explanations for mathematical problems. Let's delve into the factorization of the given polynomial expression:
Factorize the polynomial expression: 54x² + 42x³ – 30x⁴
The first step in factoring a polynomial is to identify the common factor of all the terms. In this case, the common factor is 6x².
Now, we need to factorize the quadratic expression inside the parentheses. For this, we can use methods like grouping or the quadratic formula.
Combine the factored common factor with the factored quadratic expression:
Answered on 26 Feb Learn Factorization
Nazia Khanum
To divide the expression 10(x3y2z2+x2y3z2+x2y2z3)10(x3y2z2+x2y3z2+x2y2z3) by 5x2y2z25x2y2z2, you can simplify by dividing each term in the numerator by the denominator:
Now, simplify each term:
Combine the simplified terms:
2+2+2z2+2+2z
So, the result of the division is 4+2z4+2z.
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Answered on 26 Feb Learn Factorization
Nazia Khanum
To simplify the expression 12(y2+7y+10)6(y+5)6(y+5)12(y2+7y+10), you can start by simplifying the coefficients and factoring the quadratic expression in the numerator:
12(y2+7y+10)6(y+5)6(y+5)12(y2+7y+10)
First, factor the quadratic expression in the numerator:
12(y2+7y+10)=12(y+5)(y+2)12(y2+7y+10)=12(y+5)(y+2)
Now, substitute this factorization back into the original expression:
12(y+5)(y+2)6(y+5)6(y+5)12(y+5)(y+2)
Next, simplify the coefficients and cancel out common factors:
2(y+5)(y+2)y+5y+52(y+5)(y+2)
Finally, cancel out the common factor of (y+5)(y+5):
2(y+2)2(y+2)
So, the simplified expression is 2(y+2)2(y+2).
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