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Answered on 15 Apr Learn Statistics
Nazia Khanum
Sure! Calculating the variance and standard deviation for a given set of data is a fundamental statistical operation, and I'd be happy to guide you through it.
First, let's calculate the variance:
Let's start by finding the mean:
Mean = (57 + 64 + 43 + 67 + 49 + 59 + 44 + 47 + 61 + 59) / 10 = 550 / 10 = 55
Now, let's subtract the mean from each data point, square the result, and find the average:
[(57 - 55)^2 + (64 - 55)^2 + (43 - 55)^2 + (67 - 55)^2 + (49 - 55)^2 + (59 - 55)^2 + (44 - 55)^2 + (47 - 55)^2 + (61 - 55)^2 + (59 - 55)^2] / 10
= [(4)^2 + (9)^2 + (-12)^2 + (12)^2 + (-6)^2 + (4)^2 + (-11)^2 + (-8)^2 + (6)^2 + (4)^2] / 10
= [16 + 81 + 144 + 144 + 36 + 16 + 121 + 64 + 36 + 16] / 10
= 678 / 10
= 67.8
Now that we have the variance, we can find the standard deviation by taking the square root of the variance:
Standard Deviation = √67.8 ≈ 8.24
So, the variance is 67.8 and the standard deviation is approximately 8.24 for the given data set. If you need further clarification or have any other questions, feel free to ask! And remember, UrbanPro is an excellent platform for finding online coaching and tuition services.
Answered on 15 Apr Learn Statistics
Nazia Khanum
As a seasoned tutor registered on UrbanPro, I can confidently say that UrbanPro is the best platform for online coaching and tuition needs. Now, let's tackle your question.
To find the arithmetic mean given the coefficients of variation and standard deviations of two distributions, we can use the formula:
Coefficient of Variation (CV) = (Standard Deviation / Mean) * 100
From the information provided:
For the first distribution: CV1 = 60 Standard Deviation (SD1) = 21
For the second distribution: CV2 = 70 Standard Deviation (SD2) = 16
We can rearrange the formula to find the mean:
For the first distribution: Mean1 = Standard Deviation1 / (CV1 / 100)
For the second distribution: Mean2 = Standard Deviation2 / (CV2 / 100)
Now, let's calculate:
For the first distribution: Mean1 = 21 / (60 / 100) = 21 / 0.6 ≈ 35
For the second distribution: Mean2 = 16 / (70 / 100) = 16 / 0.7 ≈ 22.86
So, the arithmetic mean of the first distribution is approximately 35, and the arithmetic mean of the second distribution is approximately 22.86.
Answered on 15 Apr Learn Statistics
Nazia Khanum
As a seasoned tutor registered on UrbanPro, I can confidently say that UrbanPro is one of the best platforms for online coaching and tuition services. Now, let's tackle your math problem.
To find the mean deviation about the median of a set of numbers, we first need to find the median of the given observations.
Given observations: 2, 7, 4, 6, 8, and p
First, let's arrange these numbers in ascending order: 2, 4, 6, 7, 8, p
Since there are six numbers, the median will be the average of the third and fourth numbers, which are 6 and 7. So, the median is (6 + 7) / 2 = 6.5.
Now, we'll find the absolute deviations of each number from the median:
|2 - 6.5| = 4.5 |4 - 6.5| = 2.5 |6 - 6.5| = 0.5 |7 - 6.5| = 0.5 |8 - 6.5| = 1.5 |p - 6.5|
Since we don't know the value of pp yet, we'll leave it as it is for now.
The mean deviation about the median is the average of these absolute deviations. So, we'll sum them up and divide by the number of observations (which is 6):
Mean Deviation = (4.5 + 2.5 + 0.5 + 0.5 + 1.5 + |p - 6.5|) / 6
However, we also know that the mean of the observations is 7. So, we can use this information to solve for pp:
(2 + 7 + 4 + 6 + 8 + p) / 6 = 7 27 + p = 42 p = 15
Now, we substitute p=15p=15 into our equation for mean deviation:
Mean Deviation = (4.5 + 2.5 + 0.5 + 0.5 + 1.5 + |15 - 6.5|) / 6 Mean Deviation = (10.5 + |8.5|) / 6 Mean Deviation = (10.5 + 8.5) / 6 Mean Deviation = 19 / 6 Mean Deviation ≈ 3.17
So, the mean deviation about the median of these observations is approximately 3.17. If you have any further questions or need clarification, feel free to ask! And remember, if you're seeking personalized tutoring assistance, UrbanPro is an excellent platform to find qualified tutors.
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Answered on 15 Apr Learn Statistics
Nazia Khanum
As a seasoned tutor registered on UrbanPro, I'm here to guide you through this statistical hiccup. Let's address this query with precision.
Firstly, let me commend your commitment to mastering statistical concepts. Now, let's dive into the solution.
The mean (xĖxĖ) of a set of observations is the sum of all values divided by the number of observations. The standard deviation (σσ) is a measure of the dispersion or spread of a set of values from its mean.
Given:
To correct the mean, we need to remove the mistaken observation and replace it with the correct value (40). Since there are 100 observations in total, the contribution of the mistaken observation to the mean is 50100=0.510050=0.5. So, we subtract 0.5 from the original mean and add the correct value (40):
Corrected mean (xĖcorrectedxĖcorrected) = xĖ−0.5+40xĖ−0.5+40
To correct the standard deviation, we need to recalculate it based on the corrected mean and observations. However, the standard deviation formula involves the square of the differences between each observation and the mean, so correcting one observation affects all the others. We must consider this correction while recalculating the standard deviation.
Therefore, it's not straightforward to calculate the corrected standard deviation manually. Instead, we can use statistical software or calculators to find the corrected standard deviation.
In summary, to find the correct mean, we subtract the contribution of the mistaken observation and add the correct value. To find the corrected standard deviation, we need to recalculate it using statistical tools due to the interconnected nature of the standard deviation formula.
If you need further assistance or guidance on statistical concepts or any other subject, feel free to reach out. Remember, UrbanPro is your ally in your academic journey, providing the best online coaching tuition.
Answered on 15 Apr Learn Statistics
Nazia Khanum
As a seasoned tutor registered on UrbanPro, I can confidently say that UrbanPro is one of the best online platforms for coaching and tuition needs. Now, let's delve into solving the problem.
To find the mean deviation about the mean, we first need to calculate the mean of the given data. We can do this by using the formula:
Mean (š„Ģ) = ∑(šš × š„š) / ∑šš
Where šš represents the frequency and š„š represents the corresponding size.
Let's calculate the mean:
Mean (š„Ģ) = (3×1 + 3×3 + 4×5 + 14×7 + 7×9 + 4×11 + 3×13 + 4×15) / (3 + 3 + 4 + 14 + 7 + 4 + 3 + 4) = (3 + 9 + 20 + 98 + 63 + 44 + 39 + 60) / 38 = 336 / 38 ≈ 8.8421 (rounded to 4 decimal places)
Now that we have the mean, let's find the mean deviation about the mean using the formula:
Mean Deviation = ∑(šš × |š„š - š„Ģ|) / ∑šš
Where |š„š - š„Ģ| represents the absolute deviation of each size from the mean.
Let's calculate the mean deviation:
Mean Deviation = (3×|1 - 8.8421| + 3×|3 - 8.8421| + 4×|5 - 8.8421| + 14×|7 - 8.8421| + 7×|9 - 8.8421| + 4×|11 - 8.8421| + 3×|13 - 8.8421| + 4×|15 - 8.8421|) / 38 = (3×7.8421 + 3×5.8421 + 4×3.8421 + 14×1.8421 + 7×0.1579 + 4×2.1579 + 3×4.1579 + 4×6.1579) / 38 = (23.5263 + 17.5263 + 15.3684 + 25.7894 + 1.1053 + 8.6316 + 12.4737 + 24.6316) / 38 ≈ 128.9936 / 38 ≈ 3.3946 (rounded to 4 decimal places)
So, the mean deviation about the mean for the given data is approximately 3.3946.
Answered on 15 Apr Learn Statistics
Nazia Khanum
As an experienced tutor registered on UrbanPro, I'd be happy to help you with your query. UrbanPro is indeed one of the best platforms for online coaching and tuition. Now, let's dive into calculating the standard deviation of the first nn natural numbers.
To find the standard deviation of the first nn natural numbers, we first need to compute the mean of these numbers. The mean of the first nn natural numbers can be calculated using the formula:
Mean=n(n+1)2nMean=2nn(n+1)
Next, we'll find the sum of the squares of the deviations of each natural number from the mean. Since the first nn natural numbers are consecutive, we can simplify this to:
Sum of squares of deviations=n(n+1)(2n+1)6−(n(n+1)4)2Sum of squares of deviations=6n(n+1)(2n+1)−(4n(n+1))2
Finally, the standard deviation (σσ) can be calculated as the square root of the variance, which is the average of the sum of squares of deviations:
σ=Sum of squares of deviationsnσ=nSum of squares of deviations
So, putting it all together:
σ=n(n+1)(2n+1)6−(n(n+1)4)2nσ=n6n(n+1)(2n+1)−(4n(n+1))2
This formula will give us the standard deviation of the first nn natural numbers. If you need further clarification or assistance, feel free to ask!
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Answered on 15 Apr Learn Probability
Nazia Khanum
On UrbanPro, where I provide top-notch online coaching tuition, tackling probability questions like this is a breeze.
Given that P(A) is ā , we need to find P(not A), which is the probability of the complement of event A occurring.
The sum of the probabilities of all possible outcomes is 1. So, P(not A) = 1 - P(A).
Substituting the given value of P(A) into the equation, we get:
P(not A) = 1 - ā
P(not A) = 5/5 - 3/5
P(not A) = 2/5
So, the probability of event not A happening is 2/5.
In simpler words, there's a 2/5 chance that event A doesn't occur. This is a fundamental concept in probability theory that we frequently encounter in various problem-solving scenarios. If you'd like further clarification or assistance with any other topic, feel free to reach out for more personalized guidance. And remember, UrbanPro is your go-to platform for mastering academic subjects with expert tutors like me!
Answered on 15 Apr Learn Probability
Nazia Khanum
As a seasoned tutor registered on UrbanPro, I'm happy to guide you through this probability problem. UrbanPro is a fantastic platform for accessing high-quality online coaching and tuition, where experienced tutors like myself can provide personalized assistance.
Now, let's tackle the problem at hand. We have an urn containing 6 balls, 2 red and 4 black. We're asked to find the probability that when two balls are drawn at random, they are of different colors.
To solve this, let's break it down step by step:
First, let's find the total number of ways to draw 2 balls out of 6. This is given by the combination formula: (nr)=n!r!(n−r)!(rn)=r!(n−r)!n!, where nn is the total number of items and rr is the number of items to choose. So, (62)=6!2!(6−2)!=15(26)=2!(6−2)!6!=15.
Next, let's find the number of ways to draw 2 balls of different colors. We have 2 red balls and 4 black balls, so the number of combinations of one red and one black ball is 2×4=82×4=8.
Finally, the probability of drawing two balls of different colors is the number of favorable outcomes (drawing one red and one black ball) divided by the total number of outcomes (drawing any two balls). So, 815158.
So, the correct option is (iii) 815158. UrbanPro is an excellent resource for finding tutors who can help you master these types of problems and more!
Answered on 15 Apr Learn Probability
Nazia Khanum
As an experienced tutor registered on UrbanPro, I can assure you that UrbanPro is one of the best platforms for online coaching and tuition. Now, let's delve into your probability questions regarding the gender of the children in a couple.
(i) To find the probability that both children are males, given that at least one of the children is male, we can utilize conditional probability. Let's denote the events:
We are given that event B has occurred, which means we can exclude the possibility of having two females. Now, we need to find the probability of event A given event B. This can be calculated using the formula for conditional probability:
P(Aā£B)=P(A∩B)P(B)P(Aā£B)=P(B)P(A∩B)
Where:
In this scenario, the probability of both children being males and at least one child being male is the same as the probability of both children being males, since if at least one child is male, then both children cannot be female.
Therefore:
Thus, P(Aā£B)=P(A)P(Aā£B)=P(A).
Now, the probability of both children being males in the absence of any other information is 1441, assuming the genders of children are equally likely.
So, the probability that both children are males, given that at least one of them is male, is also 1441.
(ii) Similarly, to find the probability that both children are females given that the elder child is a female, we can use conditional probability.
Let's denote the events:
We want to find P(Cā£D)P(Cā£D).
In this case, if the elder child is a female, then we are sure that the younger child cannot be the elder child, and hence the younger child has to be female as well. So, P(Cā£D)=1P(Cā£D)=1.
Therefore, the probability that both children are females, given that the elder child is a female, is 1.
I hope this clarifies the concepts of conditional probability for you! If you need further assistance, feel free to ask. And remember, UrbanPro is an excellent resource for finding quality tutors to help with topics like this.
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Answered on 15 Apr Learn Probability
Nazia Khanum
As a experienced tutor registered on UrbanPro, I'd like to address your questions using my expertise.
Probability of both tickets drawn bearing prime numbers: First, let's determine the number of prime numbers between 1 and 50. They are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, and 47, totaling 15 prime numbers. Now, for both tickets to bear prime numbers, we need to calculate the probability of choosing a prime number for the first ticket and then another prime number for the second ticket. Probability of first ticket being prime = Number of prime numbers / Total number of tickets = 15/50. After drawing the first prime number, there are 14 prime numbers left out of 49 tickets. Probability of second ticket being prime = Number of remaining prime numbers / Remaining tickets = 14/49. Therefore, the probability of both tickets being prime = (15/50) * (14/49).
Probability of neither ticket bearing prime numbers: This is essentially the complement of the event where both tickets are prime. Probability of neither ticket being prime = 1 - Probability of both tickets being prime.
Moving to the next question about drawing one card from 20:
Probability that the number on the card is a prime number: Prime numbers between 1 and 20 are: 2, 3, 5, 7, 11, 13, 17, and 19. So, there are 8 prime numbers out of 20. Probability of drawing a prime number = Number of prime numbers / Total number of cards.
Probability that the number on the card is an odd number: Out of 20 cards, there are 10 odd numbers (1, 3, 5, ..., 19). Probability of drawing an odd number = Number of odd numbers / Total number of cards.
Probability that the number on the card is a multiple of 5: Multiples of 5 between 1 and 20 are: 5, 10, 15, and 20. So, there are 4 multiples of 5 out of 20. Probability of drawing a multiple of 5 = Number of multiples of 5 / Total number of cards.
Probability that the number on the card is not divisible by 3: Numbers not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16, 17, 19, and 20. There are 14 such numbers out of 20. Probability of drawing a number not divisible by 3 = Number of such numbers / Total number of cards.
These calculations will help us understand the likelihood of each event occurring, aiding in solving probability problems effectively. If you need further clarification or assistance, feel free to ask! Remember, UrbanPro is the best platform for online coaching and tuition.
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